Optimal. Leaf size=227 \[ -\frac {x \left (c+d x^2\right ) \left (7 a d f (5 d e-9 c f)-b \left (24 c^2 f^2-63 c d e f+35 d^2 e^2\right )\right )}{105 f^3}+\frac {x \left (7 a d f \left (33 c^2 f^2-40 c d e f+15 d^2 e^2\right )-b \left (-48 c^3 f^3+231 c^2 d e f^2-280 c d^2 e^2 f+105 d^3 e^3\right )\right )}{105 f^4}+\frac {(b e-a f) (d e-c f)^3 \tan ^{-1}\left (\frac {\sqrt {f} x}{\sqrt {e}}\right )}{\sqrt {e} f^{9/2}}-\frac {x \left (c+d x^2\right )^2 (-7 a d f-6 b c f+7 b d e)}{35 f^2}+\frac {b x \left (c+d x^2\right )^3}{7 f} \]
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Rubi [A] time = 0.37, antiderivative size = 227, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {528, 388, 205} \[ -\frac {x \left (c+d x^2\right ) \left (7 a d f (5 d e-9 c f)-b \left (24 c^2 f^2-63 c d e f+35 d^2 e^2\right )\right )}{105 f^3}+\frac {x \left (7 a d f \left (33 c^2 f^2-40 c d e f+15 d^2 e^2\right )-b \left (231 c^2 d e f^2-48 c^3 f^3-280 c d^2 e^2 f+105 d^3 e^3\right )\right )}{105 f^4}-\frac {x \left (c+d x^2\right )^2 (-7 a d f-6 b c f+7 b d e)}{35 f^2}+\frac {(b e-a f) (d e-c f)^3 \tan ^{-1}\left (\frac {\sqrt {f} x}{\sqrt {e}}\right )}{\sqrt {e} f^{9/2}}+\frac {b x \left (c+d x^2\right )^3}{7 f} \]
Antiderivative was successfully verified.
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Rule 205
Rule 388
Rule 528
Rubi steps
\begin {align*} \int \frac {\left (a+b x^2\right ) \left (c+d x^2\right )^3}{e+f x^2} \, dx &=\frac {b x \left (c+d x^2\right )^3}{7 f}+\frac {\int \frac {\left (c+d x^2\right )^2 \left (-c (b e-7 a f)+(-7 b d e+6 b c f+7 a d f) x^2\right )}{e+f x^2} \, dx}{7 f}\\ &=-\frac {(7 b d e-6 b c f-7 a d f) x \left (c+d x^2\right )^2}{35 f^2}+\frac {b x \left (c+d x^2\right )^3}{7 f}+\frac {\int \frac {\left (c+d x^2\right ) \left (c (b e (7 d e-11 c f)-7 a f (d e-5 c f))+\left (-7 a d f (5 d e-9 c f)+b \left (35 d^2 e^2-63 c d e f+24 c^2 f^2\right )\right ) x^2\right )}{e+f x^2} \, dx}{35 f^2}\\ &=-\frac {\left (7 a d f (5 d e-9 c f)-b \left (35 d^2 e^2-63 c d e f+24 c^2 f^2\right )\right ) x \left (c+d x^2\right )}{105 f^3}-\frac {(7 b d e-6 b c f-7 a d f) x \left (c+d x^2\right )^2}{35 f^2}+\frac {b x \left (c+d x^2\right )^3}{7 f}+\frac {\int \frac {c \left (7 a f \left (5 d^2 e^2-12 c d e f+15 c^2 f^2\right )-b e \left (35 d^2 e^2-84 c d e f+57 c^2 f^2\right )\right )+\left (7 a d f \left (15 d^2 e^2-40 c d e f+33 c^2 f^2\right )-b \left (105 d^3 e^3-280 c d^2 e^2 f+231 c^2 d e f^2-48 c^3 f^3\right )\right ) x^2}{e+f x^2} \, dx}{105 f^3}\\ &=\frac {\left (7 a d f \left (15 d^2 e^2-40 c d e f+33 c^2 f^2\right )-b \left (105 d^3 e^3-280 c d^2 e^2 f+231 c^2 d e f^2-48 c^3 f^3\right )\right ) x}{105 f^4}-\frac {\left (7 a d f (5 d e-9 c f)-b \left (35 d^2 e^2-63 c d e f+24 c^2 f^2\right )\right ) x \left (c+d x^2\right )}{105 f^3}-\frac {(7 b d e-6 b c f-7 a d f) x \left (c+d x^2\right )^2}{35 f^2}+\frac {b x \left (c+d x^2\right )^3}{7 f}+\frac {\left ((b e-a f) (d e-c f)^3\right ) \int \frac {1}{e+f x^2} \, dx}{f^4}\\ &=\frac {\left (7 a d f \left (15 d^2 e^2-40 c d e f+33 c^2 f^2\right )-b \left (105 d^3 e^3-280 c d^2 e^2 f+231 c^2 d e f^2-48 c^3 f^3\right )\right ) x}{105 f^4}-\frac {\left (7 a d f (5 d e-9 c f)-b \left (35 d^2 e^2-63 c d e f+24 c^2 f^2\right )\right ) x \left (c+d x^2\right )}{105 f^3}-\frac {(7 b d e-6 b c f-7 a d f) x \left (c+d x^2\right )^2}{35 f^2}+\frac {b x \left (c+d x^2\right )^3}{7 f}+\frac {(b e-a f) (d e-c f)^3 \tan ^{-1}\left (\frac {\sqrt {f} x}{\sqrt {e}}\right )}{\sqrt {e} f^{9/2}}\\ \end {align*}
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Mathematica [A] time = 0.11, size = 179, normalized size = 0.79 \[ \frac {x \left (a d f \left (3 c^2 f^2-3 c d e f+d^2 e^2\right )-b (d e-c f)^3\right )}{f^4}+\frac {d x^3 \left (a d f (3 c f-d e)+b \left (3 c^2 f^2-3 c d e f+d^2 e^2\right )\right )}{3 f^3}+\frac {d^2 x^5 (a d f+3 b c f-b d e)}{5 f^2}+\frac {(b e-a f) (d e-c f)^3 \tan ^{-1}\left (\frac {\sqrt {f} x}{\sqrt {e}}\right )}{\sqrt {e} f^{9/2}}+\frac {b d^3 x^7}{7 f} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.94, size = 586, normalized size = 2.58 \[ \left [\frac {30 \, b d^{3} e f^{4} x^{7} - 42 \, {\left (b d^{3} e^{2} f^{3} - {\left (3 \, b c d^{2} + a d^{3}\right )} e f^{4}\right )} x^{5} + 70 \, {\left (b d^{3} e^{3} f^{2} - {\left (3 \, b c d^{2} + a d^{3}\right )} e^{2} f^{3} + 3 \, {\left (b c^{2} d + a c d^{2}\right )} e f^{4}\right )} x^{3} - 105 \, {\left (b d^{3} e^{4} + a c^{3} f^{4} - {\left (3 \, b c d^{2} + a d^{3}\right )} e^{3} f + 3 \, {\left (b c^{2} d + a c d^{2}\right )} e^{2} f^{2} - {\left (b c^{3} + 3 \, a c^{2} d\right )} e f^{3}\right )} \sqrt {-e f} \log \left (\frac {f x^{2} - 2 \, \sqrt {-e f} x - e}{f x^{2} + e}\right ) - 210 \, {\left (b d^{3} e^{4} f - {\left (3 \, b c d^{2} + a d^{3}\right )} e^{3} f^{2} + 3 \, {\left (b c^{2} d + a c d^{2}\right )} e^{2} f^{3} - {\left (b c^{3} + 3 \, a c^{2} d\right )} e f^{4}\right )} x}{210 \, e f^{5}}, \frac {15 \, b d^{3} e f^{4} x^{7} - 21 \, {\left (b d^{3} e^{2} f^{3} - {\left (3 \, b c d^{2} + a d^{3}\right )} e f^{4}\right )} x^{5} + 35 \, {\left (b d^{3} e^{3} f^{2} - {\left (3 \, b c d^{2} + a d^{3}\right )} e^{2} f^{3} + 3 \, {\left (b c^{2} d + a c d^{2}\right )} e f^{4}\right )} x^{3} + 105 \, {\left (b d^{3} e^{4} + a c^{3} f^{4} - {\left (3 \, b c d^{2} + a d^{3}\right )} e^{3} f + 3 \, {\left (b c^{2} d + a c d^{2}\right )} e^{2} f^{2} - {\left (b c^{3} + 3 \, a c^{2} d\right )} e f^{3}\right )} \sqrt {e f} \arctan \left (\frac {\sqrt {e f} x}{e}\right ) - 105 \, {\left (b d^{3} e^{4} f - {\left (3 \, b c d^{2} + a d^{3}\right )} e^{3} f^{2} + 3 \, {\left (b c^{2} d + a c d^{2}\right )} e^{2} f^{3} - {\left (b c^{3} + 3 \, a c^{2} d\right )} e f^{4}\right )} x}{105 \, e f^{5}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.49, size = 307, normalized size = 1.35 \[ \frac {{\left (a c^{3} f^{4} - b c^{3} f^{3} e - 3 \, a c^{2} d f^{3} e + 3 \, b c^{2} d f^{2} e^{2} + 3 \, a c d^{2} f^{2} e^{2} - 3 \, b c d^{2} f e^{3} - a d^{3} f e^{3} + b d^{3} e^{4}\right )} \arctan \left (\sqrt {f} x e^{\left (-\frac {1}{2}\right )}\right ) e^{\left (-\frac {1}{2}\right )}}{f^{\frac {9}{2}}} + \frac {15 \, b d^{3} f^{6} x^{7} + 63 \, b c d^{2} f^{6} x^{5} + 21 \, a d^{3} f^{6} x^{5} - 21 \, b d^{3} f^{5} x^{5} e + 105 \, b c^{2} d f^{6} x^{3} + 105 \, a c d^{2} f^{6} x^{3} - 105 \, b c d^{2} f^{5} x^{3} e - 35 \, a d^{3} f^{5} x^{3} e + 35 \, b d^{3} f^{4} x^{3} e^{2} + 105 \, b c^{3} f^{6} x + 315 \, a c^{2} d f^{6} x - 315 \, b c^{2} d f^{5} x e - 315 \, a c d^{2} f^{5} x e + 315 \, b c d^{2} f^{4} x e^{2} + 105 \, a d^{3} f^{4} x e^{2} - 105 \, b d^{3} f^{3} x e^{3}}{105 \, f^{7}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 401, normalized size = 1.77 \[ \frac {b \,d^{3} x^{7}}{7 f}+\frac {a \,d^{3} x^{5}}{5 f}+\frac {3 b c \,d^{2} x^{5}}{5 f}-\frac {b \,d^{3} e \,x^{5}}{5 f^{2}}+\frac {a c \,d^{2} x^{3}}{f}-\frac {a \,d^{3} e \,x^{3}}{3 f^{2}}+\frac {b \,c^{2} d \,x^{3}}{f}-\frac {b c \,d^{2} e \,x^{3}}{f^{2}}+\frac {b \,d^{3} e^{2} x^{3}}{3 f^{3}}+\frac {a \,c^{3} \arctan \left (\frac {f x}{\sqrt {e f}}\right )}{\sqrt {e f}}-\frac {3 a \,c^{2} d e \arctan \left (\frac {f x}{\sqrt {e f}}\right )}{\sqrt {e f}\, f}+\frac {3 a c \,d^{2} e^{2} \arctan \left (\frac {f x}{\sqrt {e f}}\right )}{\sqrt {e f}\, f^{2}}-\frac {a \,d^{3} e^{3} \arctan \left (\frac {f x}{\sqrt {e f}}\right )}{\sqrt {e f}\, f^{3}}-\frac {b \,c^{3} e \arctan \left (\frac {f x}{\sqrt {e f}}\right )}{\sqrt {e f}\, f}+\frac {3 b \,c^{2} d \,e^{2} \arctan \left (\frac {f x}{\sqrt {e f}}\right )}{\sqrt {e f}\, f^{2}}-\frac {3 b c \,d^{2} e^{3} \arctan \left (\frac {f x}{\sqrt {e f}}\right )}{\sqrt {e f}\, f^{3}}+\frac {b \,d^{3} e^{4} \arctan \left (\frac {f x}{\sqrt {e f}}\right )}{\sqrt {e f}\, f^{4}}+\frac {3 a \,c^{2} d x}{f}-\frac {3 a c \,d^{2} e x}{f^{2}}+\frac {a \,d^{3} e^{2} x}{f^{3}}+\frac {b \,c^{3} x}{f}-\frac {3 b \,c^{2} d e x}{f^{2}}+\frac {3 b c \,d^{2} e^{2} x}{f^{3}}-\frac {b \,d^{3} e^{3} x}{f^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 2.03, size = 266, normalized size = 1.17 \[ \frac {{\left (b d^{3} e^{4} + a c^{3} f^{4} - {\left (3 \, b c d^{2} + a d^{3}\right )} e^{3} f + 3 \, {\left (b c^{2} d + a c d^{2}\right )} e^{2} f^{2} - {\left (b c^{3} + 3 \, a c^{2} d\right )} e f^{3}\right )} \arctan \left (\frac {f x}{\sqrt {e f}}\right )}{\sqrt {e f} f^{4}} + \frac {15 \, b d^{3} f^{3} x^{7} - 21 \, {\left (b d^{3} e f^{2} - {\left (3 \, b c d^{2} + a d^{3}\right )} f^{3}\right )} x^{5} + 35 \, {\left (b d^{3} e^{2} f - {\left (3 \, b c d^{2} + a d^{3}\right )} e f^{2} + 3 \, {\left (b c^{2} d + a c d^{2}\right )} f^{3}\right )} x^{3} - 105 \, {\left (b d^{3} e^{3} - {\left (3 \, b c d^{2} + a d^{3}\right )} e^{2} f + 3 \, {\left (b c^{2} d + a c d^{2}\right )} e f^{2} - {\left (b c^{3} + 3 \, a c^{2} d\right )} f^{3}\right )} x}{105 \, f^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.85, size = 312, normalized size = 1.37 \[ x\,\left (\frac {b\,c^3+3\,a\,d\,c^2}{f}+\frac {e\,\left (\frac {e\,\left (\frac {a\,d^3+3\,b\,c\,d^2}{f}-\frac {b\,d^3\,e}{f^2}\right )}{f}-\frac {3\,c\,d\,\left (a\,d+b\,c\right )}{f}\right )}{f}\right )+x^5\,\left (\frac {a\,d^3+3\,b\,c\,d^2}{5\,f}-\frac {b\,d^3\,e}{5\,f^2}\right )-x^3\,\left (\frac {e\,\left (\frac {a\,d^3+3\,b\,c\,d^2}{f}-\frac {b\,d^3\,e}{f^2}\right )}{3\,f}-\frac {c\,d\,\left (a\,d+b\,c\right )}{f}\right )+\frac {b\,d^3\,x^7}{7\,f}+\frac {\mathrm {atan}\left (\frac {\sqrt {f}\,x\,\left (a\,f-b\,e\right )\,{\left (c\,f-d\,e\right )}^3}{\sqrt {e}\,\left (-b\,c^3\,e\,f^3+a\,c^3\,f^4+3\,b\,c^2\,d\,e^2\,f^2-3\,a\,c^2\,d\,e\,f^3-3\,b\,c\,d^2\,e^3\,f+3\,a\,c\,d^2\,e^2\,f^2+b\,d^3\,e^4-a\,d^3\,e^3\,f\right )}\right )\,\left (a\,f-b\,e\right )\,{\left (c\,f-d\,e\right )}^3}{\sqrt {e}\,f^{9/2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 1.49, size = 508, normalized size = 2.24 \[ \frac {b d^{3} x^{7}}{7 f} + x^{5} \left (\frac {a d^{3}}{5 f} + \frac {3 b c d^{2}}{5 f} - \frac {b d^{3} e}{5 f^{2}}\right ) + x^{3} \left (\frac {a c d^{2}}{f} - \frac {a d^{3} e}{3 f^{2}} + \frac {b c^{2} d}{f} - \frac {b c d^{2} e}{f^{2}} + \frac {b d^{3} e^{2}}{3 f^{3}}\right ) + x \left (\frac {3 a c^{2} d}{f} - \frac {3 a c d^{2} e}{f^{2}} + \frac {a d^{3} e^{2}}{f^{3}} + \frac {b c^{3}}{f} - \frac {3 b c^{2} d e}{f^{2}} + \frac {3 b c d^{2} e^{2}}{f^{3}} - \frac {b d^{3} e^{3}}{f^{4}}\right ) - \frac {\sqrt {- \frac {1}{e f^{9}}} \left (a f - b e\right ) \left (c f - d e\right )^{3} \log {\left (- \frac {e f^{4} \sqrt {- \frac {1}{e f^{9}}} \left (a f - b e\right ) \left (c f - d e\right )^{3}}{a c^{3} f^{4} - 3 a c^{2} d e f^{3} + 3 a c d^{2} e^{2} f^{2} - a d^{3} e^{3} f - b c^{3} e f^{3} + 3 b c^{2} d e^{2} f^{2} - 3 b c d^{2} e^{3} f + b d^{3} e^{4}} + x \right )}}{2} + \frac {\sqrt {- \frac {1}{e f^{9}}} \left (a f - b e\right ) \left (c f - d e\right )^{3} \log {\left (\frac {e f^{4} \sqrt {- \frac {1}{e f^{9}}} \left (a f - b e\right ) \left (c f - d e\right )^{3}}{a c^{3} f^{4} - 3 a c^{2} d e f^{3} + 3 a c d^{2} e^{2} f^{2} - a d^{3} e^{3} f - b c^{3} e f^{3} + 3 b c^{2} d e^{2} f^{2} - 3 b c d^{2} e^{3} f + b d^{3} e^{4}} + x \right )}}{2} \]
Verification of antiderivative is not currently implemented for this CAS.
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